|Name:||CSIR NET JRF June 2019 Online Form|
|Exam Full Name::||CSIR-UGC National Eligibility Test 2019|
|Category:||Central Competition Exam|
Exam Name – CSIR-UGC National Eligibility Test(NET) for Junior Research Fellowship(JRF & for Lectureship(LS)
Council of Scientific and Industrial Research (CSIR), New Delhi invited applications for the Single MCQ Examination (Joint CSIR - UGC Test) for the Award of Junior Research Fellowship (JRF) NET and appointment for Lecturer (NET).
Educational Qualification –
(a) Candidates Having Masters in Science Stream(M.SC)/Equivalent Degree with 55% Marks(Gen/OBC Candidates) & 50% Marks(SC/ST/PH Candidates will be eligible for CSIR Examination.
(b) Candidates having Integrated Courses such as B.E/B.Tech/B.Pharma & MBBS Candidates are also eligible for CSIR NET 2018.
How to Apply - Candidates can apply through official site of the CSIR before 18/March/2019.
Mode of Selection- Written Examination